chemical kinetics

By Sandesh in 31 Aug 2024 | 09:56 pm
Sandesh

Sandesh

Student
Posts: 1
Likes: 2
Member since: 31 Aug 2024

In a first order reaction, the concentration of the reactant decreased from 1M to 0.25 M in 20 minutes. The rate constant of the reaction is

31 Aug 2024 | 09:56 pm
2 Likes
MentorJi

MentorJi

Staff
VIP Mentor
Posts: 115
Likes: 6
Member since: 20 Feb 2024

To determine the rate constant kk for a first-order reaction where the concentration of the reactant decreases from 1 M to 0.25 M in 20 minutes, we can use the integrated rate law for first-order reactions:

ln⁡[A]=ln⁡[A0]−ktln[A]=ln[A0]−kt

Where:

  • [A0][A0] is the initial concentration (1 M),
  • [A][A] is the concentration at time tt (0.25 M),
  • tt is the time in seconds (20 minutes = 1200 seconds),
  • kk is the rate constant.

First, we calculate the natural logarithm of the concentrations:

ln⁡[1]=0ln[1]=0
ln⁡[0.25]=−1.3863ln[0.25]=−1.3863

Now, substituting these values into the integrated rate law:

−1.3863=0−k(1200)−1.3863=0−k(1200)

Rearranging gives:

k=1.38631200k=12001.3863

Calculating kk:

k≈0.001155 s−1k≈0.001155s−1

Thus, the rate constant kk for the reaction is approximately 0.001155 s−10.001155s−1.

31 Aug 2024 | 10:12 pm
0 Likes
Love Malhotra

Love Malhotra

Student
Posts: 22
Likes: 1
Member since: 20 Feb 2024
31 Aug 2024 | 10:18 pm
0 Likes

Report

Please describe about the report short and clearly.